-9x^2-4x+5=0

Solution for -9x^2-4x+5=0 equation:

-9x^2-4x+5=0

a = -9; b = -4; c = +5;
Δ = b2-4ac
Δ = -42-4·(-9)·5
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-14}{2*-9}=\frac{-10}{-18}
=5/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+14}{2*-9}=\frac{18}{-18}
=-1
$